function vand_ex_2_1()
% Solution to Exercise 2.1 of Vanderbei.
% Michael Floater, 3 Feb 2020.

dict0 = [0,6,8,5,9;5,-2,-1,-1,-3;3,-1,-3,-1,-2];
dict1 = pivot(dict0,4,2)
dict2 = pivot(dict1,1,1)
dict3 = pivot(dict2,2,2)
dict4 = pivot(dict3,3,2)

